If f(x) = x^3 + 1, find f^{-1}(2010).
Let
\(y=x^3+1\\ y-1=x^3\\ x=\sqrt[3]{y-1}\\ so\; if\\ f(x)=x^3+1\\ f^{-1}(x)=\sqrt[3]{x-1}\\ f^{-1}(2010)=\sqrt[3]{2010-1}\\ f^{-1}(2010)=\sqrt[3]{2009}\\ \)