+964 Find the discriminant of the quadratic 5x^2 - 2x + 8 - 2x^2 + 6x + 2 - 2x^2 + 4x - 1.
+1908 Tottenham10, you did a great job with simplifying the quadratic, but there was one tiny mistake.
The descriminant is \(b^2-4ac\), not \(\sqrt{b^2-4ac}\). Other than that, you're good!
So, now we...
First, let's combine all like terms. We get;
\(x^{2}+8x+9\)
Now, the decriminant is \(b^2-4ac\) for any quadratics in the form of \(ax^2+bx+c\)
Thus, plugging in the numbers in the quadratic we have, we get
\(8^2-4(1)(9) \\ = 64- 36\\ =28\)
So 28 is our answer.
Thanks! :)
+42 If we combine all the like terms, the expression turns into \(x^2+8x+9\). The discriminant is \(\sqrt{b^2-4ac}\), so if we just plug in the values, we get \(\sqrt{64-36}=\sqrt{28}=2\sqrt{7}\).
Feel free to tell me if I made a mistake! :D
+1908 Tottenham10, you did a great job with simplifying the quadratic, but there was one tiny mistake.
The descriminant is \(b^2-4ac\), not \(\sqrt{b^2-4ac}\). Other than that, you're good!
So, now we...
First, let's combine all like terms. We get;
\(x^{2}+8x+9\)
Now, the decriminant is \(b^2-4ac\) for any quadratics in the form of \(ax^2+bx+c\)
Thus, plugging in the numbers in the quadratic we have, we get
\(8^2-4(1)(9) \\ = 64- 36\\ =28\)
So 28 is our answer.
Thanks! :)
