If x + y = 5 and xy = 3, then compute x^3 + y^3.
(x+y)^3 = ( x^3 + y^3) + 3x^2y + 3xy^2
125 = (x^3 + y^3) + 3 (15 ) (x+y)(xy) = x^2 y + xy^2
80 = x3 + y3
good job ep nice.