+193 What is the solution of the linear-quadratic system of equations?
+37146 The first one is a parabola....the second is a line....so there COULD be TWO solutions....or ONE ...or none.
Re arrange second equation y = x+2 and sub it into FIRST equation
x+2 = x^2 + 5x-3 simplify
x^2 - 4x -5 = 0
(x-5)(x+1) = 0 so x = 5 and - 1
sub these values into SECOND equation to find the corresponding 'y'
5,7 and -1,1
+37146 The first one is a parabola....the second is a line....so there COULD be TWO solutions....or ONE ...or none.
Re arrange second equation y = x+2 and sub it into FIRST equation
x+2 = x^2 + 5x-3 simplify
x^2 - 4x -5 = 0
(x-5)(x+1) = 0 so x = 5 and - 1
sub these values into SECOND equation to find the corresponding 'y'
5,7 and -1,1
