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What is the solution of the linear-quadratic system of equations?

 Dec 19, 2018

Best Answer 

 #1
avatar+18311 
+3

The first one is a parabola....the second is a line....so there COULD be TWO solutions....or ONE ...or none.

 

Re arrange second equation    y = x+2    and sub it into FIRST equation

x+2 = x^2 + 5x-3      simplify

x^2 - 4x -5 = 0       

(x-5)(x+1) = 0     so x = 5 and - 1

 

sub these values  into SECOND equation to find the corresponding 'y'

 

5,7    and  -1,1

 Dec 19, 2018
 #1
avatar+18311 
+3
Best Answer

The first one is a parabola....the second is a line....so there COULD be TWO solutions....or ONE ...or none.

 

Re arrange second equation    y = x+2    and sub it into FIRST equation

x+2 = x^2 + 5x-3      simplify

x^2 - 4x -5 = 0       

(x-5)(x+1) = 0     so x = 5 and - 1

 

sub these values  into SECOND equation to find the corresponding 'y'

 

5,7    and  -1,1

ElectricPavlov Dec 19, 2018

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