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The sum 1^2 + 2^2 + 3^2 + ... + n^2 = n(n + 1)(2n + 1)/6.

 

What is the value of 21^2 + 22^2 + 23^2 + ... + 40^2 + 41^2 + 42^2?

 Oct 8, 2021
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What is the value of 21^2 + 22^2 + 23^2 + ... + 40^2 + 41^2 + 42^2?

 

sumfor(n, 21, 42, n^2)==22,715

 Oct 8, 2021

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