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What is the sum of all real values of x that satisfy the equation (x-3)(x^2+4x+4)=x-3+x^3-7x+8?

 Jun 18, 2022
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(x - 3)(x^2 + 4x + 4) = x - 3 + x^3 - 7x + 8

x^3 + x^2 - 8x - 12 = x^3 - 6x + 5

x^2 - 8x - 12 = -6x + 5

x^2 - 2x - 17 = 0

 

From there, use the quadratic formula and add the roots to get the answer.

 Sep 25, 2022

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