Algebra

first, re-write the equation in LaTeX.

${1\over2}y+{1\over4}=3+\boxed{\phantom{400}}y$

Instead of a box, substitute it for x.

${1\over2}y+{1\over4}=3+xy$

To get rid of the fractions, multiply both sides by 4.

$4*({1\over2}y+{1\over4})=(3+xy)*4$

simplified...

$2y+1=12+4xy$

move all numbers to one side

$(2y+1)-(2y+1)=12+4xy-(2y+1)$

simplified...

$4xy-2y+11=0$

the easiest way to get more than one solution is to make the equation a binomial.

to make $4xy-2y+11=0$ a binomial, we can just say that x=y

simplified...

$4y^2-2y+11=0$

since x=y, y must be placed in the box.

The only thing I am worried about is that it might not want a variable for the box, but instead an actual number.