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Let a_1, a_2, a_3, \dots, a_8, a_9, a_{10} be an arithmetic sequence. If $a_1 + a_3 = 5$ and $a_2 + a_4 = 6$, then find $a_1$.

 Jan 26, 2025
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Let a_1, a_2, a_3, \dots, a_8, a_9, a_{10} be an arithmetic sequence. If $a_1 + a_3 = 5$ and $a_2 + a_4 = 6$, then find $a_1$.    

 

call "d" the amount of addition between successive terms.    

 

starting with a1   then  a2  =  a1 + d                                              =   a1 + d     

                                    a3  =  a2 + d  =  (a1 + d) + d                     =   a1 + 2d    

                                    a4  =  a3 + d  =  (a1 + d + d) + d               =   a1 + 3d    

                                    a5  =  a4 + d  =  (a1 + d + d + d) + d         =   a1 + 4d    

                                    a6  =  a5 + d  =  (a1 + d + d + d + d) + d   =   a1 + 5d    etc. . . .    

 

given       a1 + a3  =  5   

                a1 + (a1 + 2d)  =  5   

                2a1 + 2d  =  5                                   (eq 1)    

 

given        a2 + a4  =  6   

                (a1 + d) + (a1 + 3d)  =  6   

                2a1 + 4d  =  6    

                  a1 + 2d  =  3                                    (eq 2)    

 

Subtract (eq 2) from (eq 1)    

                                               2a1 + 2d  =  5      (eq 1)    

                                                 a1 + 2d  =  3      (eq 2)    

                                                 a1          =  2    

.    

 Jan 27, 2025
edited by Bosco  Jan 27, 2025

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