Bottle A contains more soda than Bottle B. Pour from Bottle A into Bottle B as much soda as B already contains. Now pour from B into A as much soda as A now contains. Then pour from A into B as much soda as B now contains. Each bottle now contains 64 ounces. How many more ounces of soda were in Bottle A than Bottle B at the beginning?

Guest Jul 9, 2020

#1**0 **

Let the initial amount of soda in bottle A=S

Let the initial amount of soda in bottle B= T

Bottle A now has =S - T

Bottle B now has =2T

Bottle B now has =2T - [S - T]

Bottle A now has =2[S - T]

Bottle B now has =2[2T - (S - T)] =64,

Bottle A now has =4[S - T] =64, solve for S, T

**S = 40 ounces - the initial amount of soda in bottle A T = 24 ounces -the initial amount of soda in bottle B 40 - 24 = 16 more ounces of soda initially in bottle A than bottle B**

Guest Jul 9, 2020