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Bottle A contains more soda than Bottle B. Pour from Bottle A into Bottle B as much soda as B already contains. Now pour from B into A as much soda as A now contains. Then pour from A into B as much soda as B now contains. Each bottle now contains 64 ounces. How many more ounces of soda were in Bottle A than Bottle B at the beginning?

 Jul 9, 2020
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Let the initial amount of soda in bottle A=S
Let the initial amount of soda in bottle B= T
Bottle A now has =S - T
Bottle B now has =2T
Bottle B now has =2T - [S - T]
Bottle A now has =2[S - T]


Bottle B now has =2[2T - (S - T)] =64,
Bottle A now has =4[S - T] =64, solve for S, T


S = 40 ounces - the initial amount of soda in bottle A
T = 24 ounces -the initial amount of soda in bottle B
40 - 24 = 16 more ounces of soda initially in bottle A than bottle B

 Jul 9, 2020

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