+286 Find the vertices of the hyperbola from part (a).
-4x^2 + y^2 - 2y = -3y^2 + 8x + 9y + 15
+130462 Simplify as
4y^2 -11y - 4x^2 -8x = 15 complete the square on x, y
4 (y^2 - (11/4)y + 121/64) - 4(x^2 + 2x + 1) = 15 + 121/64 - 4
4( y - 11/8)^2 - 4(x + 1)^2 = 297/16
(y -11/8)^2 - ( x + 1)^2 = 1
__________ ________
297/64 297/64
Vertices = (-1, 11/8 +/- sqrt (297) / 8 )
