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Solve for the variable x in terms of y and z, assuming y \neq \frac{1}{2}:
xy + x = \frac{3x + 2y + z + y + 2z}{3}

 Jun 5, 2024
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\(xy + x = \frac{3x + 2y + z + y + 2z}{3} \)

 

3x (y + 1) =  3x + 2y + z + y + 2z

 

3x (y+ 1) - 3x = 3y + 3z

 

3x (y + 1 - 1)  = 3 (y + z)

 

x (y )  = (y + z)

 

         ( y + z)

x =     _________

               y 

 

 

cool cool cool

 Jun 6, 2024

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