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Algebra

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For what real values of $c$ is $x^2 - 8x - 4x + c + x^2 - 20x + x^2$ the square of a binomial?

LiIIiam0216 Jun 9, 2024

Best Answer

+1950

+1

First, let's combine all like terms.

We have $3x^{2}-32x+c$ as the simplified version.

Now, let's divide everything by 3 to make our lives idea.

We get $x^2-\frac{32}{3}x+c/3$ .

Now, we divide 32/3 by 2, and we get $16/3$

Now, $(16/3)^2 = 256/9$ .

Now, we have

$c/3 = 256/9\\ c=253/3$

Thanks! :)

NotThatSmart Jun 9, 2024

1⁺⁰ Answers

+1950

+1

Best Answer

First, let's combine all like terms.

We have $3x^{2}-32x+c$ as the simplified version.

Now, let's divide everything by 3 to make our lives idea.

We get $x^2-\frac{32}{3}x+c/3$ .

Now, we divide 32/3 by 2, and we get $16/3$

Now, $(16/3)^2 = 256/9$ .

Now, we have

$c/3 = 256/9\\ c=253/3$

Thanks! :)

NotThatSmart Jun 9, 2024

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