Algebra

Let's first find u and v. Carrying all terms to one side and combining like terms, we get $x^2-6x+13=0$

Using the quadratic equation, we get $x=3+2i,\:x=3-2i$, meaning we have $u =3-2i$ and $v =3+2i$.

Plugging these values into $u/v^2 + v/u^2$, we get $\frac{3-2i}{(3+2i)^2} + \frac{3+2i}{(3-2i)^2}$

Simplifying the expression gets us the fraction $-\frac{18}{169}$

Thanks! :)