Find the sum of the squares of the roots of $2x^2+4x-1=x^2-8x+3$.
Combining like terms and moving all terms to one side, we get
x2+12x−4=0
Using the quadratic equation, we get
x=−12±√122−4⋅1(−4)2⋅1
Finally simplifying, we get
x=2√10−6x=−2√10−6
Thanks! :)
x^2 + 12x - 4 = 0
Let the roots be a,b
ab = -4
2ab = -8
a + b = -12 square both sides
a^2 + 2ab + b^2 =144
a^2 - 8 + b^2 = 144
a^2 + b^2 = 152
+1950 
