Algebra

Combining like terms and moving all terms to one side, we get

\(x^{2}+12x-4=0\)

Using the quadratic equation, we get

\(x=\frac{-12\pm \sqrt{12^{2}-4\cdot 1(-4)}}{2\cdot 1}\)

Finally simplifying, we get

\(x=2\sqrt{10}-6\\ x=-2\sqrt{10}-6\)

Thanks! :)

x^2 + 12x - 4 = 0

Let the roots be a,b

ab  = -4

2ab = -8

a + b = -12       square both sides

a^2 + 2ab + b^2 =144

a^2 - 8 + b^2  = 144

a^2 + b^2 = 152