+834 Find all values of x such that \frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}.
+118677 mmm
\(\frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}\)
for starters x cannot equal 5, 2 or -3
\(\frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}\\ \frac{x}{x - 5} = \frac{2}{x - 2} + \frac{2}{x + 3}\\ x(x-2)(x+3)=2(x-5)(x+3)+2(x-5)(x-2)\)
Now expand out and see where it goes.
It did not fall out for me.
