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Find all values of x such that \frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}.

 May 27, 2024
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mmm

 

\(\frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}\)

 

for starters x cannot equal  5, 2 or  -3

 

\(\frac{x}{x - 5} = \frac{4}{2x - 4} + \frac{2}{x + 3}\\ \frac{x}{x - 5} = \frac{2}{x - 2} + \frac{2}{x + 3}\\ x(x-2)(x+3)=2(x-5)(x+3)+2(x-5)(x-2)\)

 

Now expand out and see where it goes.

 

It did not fall out for me.

 

 May 28, 2024

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