Let $a$ and $b$ be complex numbers. If $a + b = 4$ and $a^2 + b^2 = 6,$ then what is $a^3 + b^3?$
We can use the fact (a+b)3=a3+3a2b+3ab2+b3 to our advantage.
Expanding the left side, we get
(a+b)3=a3+3a2b+3ab2+b3 =a3+b3+3ab(a+b).
Since we are given that a+b=4, this becomes a^3 + b^3 + 3ab(4) = 6.
Then a^3 + b^3 = −10.