A father is 38 years old, his sons are 13 and 5 years old, and his daughter is 8 years old. In how many years will the father be the same age as his children put together?

Let X be the number of years

36 + X = (13 + X) + (5 + X) +(8 + X)

36 + X = 26 + 3X

36 – 26 = 3X – X

2X = 10

X = 5

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Hey, I copied the problem wrong. Father is 38 not 36.

So it would be 38 – 26 = 3X – X

2X = 12

X = 6

Sorry for the previous error.

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