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A father is 38 years old, his sons are 13 and 5 years old, and his daughter is 8 years old. In how many years will the father be the same age as his children put together?

 Jul 10, 2020
 #1
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Let X be the number of years 

 

36 + X  =  (13 + X) + (5 + X) +(8 + X)  

 

36 + X  =  26 + 3X 

 

36 – 26  =  3X – X  

 

        2X  =  10 

 

          X  =  5 

.

 Jul 10, 2020
 #2
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Hey, I copied the problem wrong.  Father is 38 not 36. 

 

So it would be       38 – 26  =  3X – X       

 

                                     2X  =  12    

 

                                       X  =  6 

 

Sorry for the previous error.  

π

Guest Jul 10, 2020
edited by Guest  Jul 10, 2020

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