Find the vertex of the graph of the equation x - y^2 + 8y = 13 + 4y + y^2
Simplify by combining 'like' tems
x = 2y^2 -4y +13 a sideways parabola the 'y' coordinate of the vertex will be found by -b/2a = - -4/(2*2) = 1
the 'x' coordinate will be found by substituting y = 1 into the equation = 11
