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The function f(x) is defined for 1 \le x \le 5 as follows:

f(x) = 2x + 8 if 1 \le x \le 2

f(x) = 13 - 5x if 2 < x \le 3

f(x) = 20 - 14x if 3 < x \le 4

f(x) = 40 + 5x if 4 < x \le 5

 

Find all real numbers x such that f(x) = x.  If you find more than one answer, list them all, separated by commas.

 Dec 2, 2024
 #1
avatar+1946 
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For this problem, we have to go throug every function and find when f(x) = x. 

 

First off, we have f(x)=2x+8

We have to solve 2x+8=x, in which we get x=8. However, -8 isn't in the range 1x2, so it isn't a valid solution. 

 

Next, we have f(x)=135x

Solving for 135x=x, we get x=13/6. Indeed, 13/6 is in the range 2<x3, so it is a valid solution. 

 

After, we have f(x)=2014x

Solving for 2014x=x, we get x=4/3, which is not a valid solution since it's not in the range 3<x4

 

Lastly, we have f(x)=40+5x

We have 40+5x=x, in which we get x=10, which is not a valid solution. 

 

So, we only have x = 13/6

 

Thanks! :)

 Dec 2, 2024
edited by NotThatSmart  Dec 2, 2024

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