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Rewrite the expression 6j^2 - 6j - 12 in the form c(j + p)^2 + q, where c, p, and q are constants. What is q/p?

 Feb 2, 2022
 #1
avatar+1365 
+2

The equation can be written as \(6(j^2-j-2)\)

 

We can divide the equation by \(6\) to get \(j^2-j-2\)

 

This is: \(j^2-j-2=0\)

 

Add \(2\) to both sides: \(j^2-j=2\)

 

Rewrite: \((j-0.5)^2 = 2+0.25\)

 

So: \(6(j-0.5)^2 = 6j^2-6j+1.5\)

 

We need to subtract \(13\) to get the equation, so we have: \(6(j-0.5)^2-13\)

 

Thus, the answer is \({-13\over-0.5} = \color{brown}\boxed{26}\)

 Feb 3, 2022
edited by BuilderBoi  Feb 3, 2022
 #2
avatar+63 
+3

Nevermind wrong thing!!!

 

⚡⚡⚡

ShockFish

 Feb 3, 2022
edited by ShockFish  Feb 3, 2022

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