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# Algebra

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Rewrite the expression 6j^2 - 6j - 12 in the form c(j + p)^2 + q, where c, p, and q are constants. What is q/p?

Feb 2, 2022

#1
+1365
+2

The equation can be written as $$6(j^2-j-2)$$

We can divide the equation by $$6$$ to get $$j^2-j-2$$

This is: $$j^2-j-2=0$$

Add $$2$$ to both sides: $$j^2-j=2$$

Rewrite: $$(j-0.5)^2 = 2+0.25$$

So: $$6(j-0.5)^2 = 6j^2-6j+1.5$$

We need to subtract $$13$$ to get the equation, so we have: $$6(j-0.5)^2-13$$

Thus, the answer is $${-13\over-0.5} = \color{brown}\boxed{26}$$

Feb 3, 2022
edited by BuilderBoi  Feb 3, 2022
#2
+63
+3

Nevermind wrong thing!!!

⚡⚡⚡

ShockFish

Feb 3, 2022
edited by ShockFish  Feb 3, 2022