Algebra

The equation can be written as $6(j^2-j-2)$. 

We can divide the equation by $6$ to get $j^2-j-2$. 

This is: $j^2-j-2=0$

Add $2$ to both sides: $j^2-j=2$

Rewrite: $(j-0.5)^2 = 2+0.25$

So: $6(j-0.5)^2 = 6j^2-6j+1.5$

We need to subtract $13$ to get the equation, so we have: $6(j-0.5)^2-13$

Thus, the answer is ${-13\over-0.5} = \color{brown}\boxed{26}$

Nevermind wrong thing!!!

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ShockFish