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What is the value of m, if the equation my^2+2y−4=0 has exactly one root?

 May 8, 2016

Best Answer 

 #1
avatar+37170 
+5

my^2 +2y - 4 = 0

Use quadratic formula to find    the only way for one root is sqrt( 4+16m)  = 0     so m = -1/4

 

   Leaving the only y= 4        root

 May 8, 2016
edited by ElectricPavlov  May 8, 2016
 #1
avatar+37170 
+5
Best Answer

my^2 +2y - 4 = 0

Use quadratic formula to find    the only way for one root is sqrt( 4+16m)  = 0     so m = -1/4

 

   Leaving the only y= 4        root

ElectricPavlov May 8, 2016
edited by ElectricPavlov  May 8, 2016
 #2
avatar-14 
+5

my^2+2y-4=0

-4(y^-2)+2(y^-1)+m=0

4(y^-2)-2(y^-1)-m=0

4(y^-2)-2(y^-1)=m

(2(y^-1)-0.5)=4(y^-2)-2(y^-1)-m

(2(y^-1)-0.5)=0

m=-0.25

y=4

 

That's what you meant by one root, right?

 May 8, 2016

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