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Find the minimum value of \frac{x^2}{x - 1 + x^3} for x > 1

 Jul 18, 2024
 #1
avatar+1908 
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There actually is no minimum value. 

The larger x gets, the smaller the fraction becomes, therefore meaning there is no minimum value. 

The range is  \(y <1\), meaning no minimum value is present. 

 

Here's an image

The horizontal asymtote is \(y=0\)

 

Thanks! :)

 Jul 18, 2024
edited by NotThatSmart  Jul 18, 2024

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