Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to 4/3 times the largest of the seven integers. What is the smallest integer that Pearl wrote down?
Let the numbers be x−3,x−2,x−1,x,x+1,x+2,x+3
Their sum is
7x=43(x+3)
Solving we get:
x=1217
The largest number is x+3=1217+31=6317
Which is not an integer and the question is flawed.
Let the numbers be x−3,x−2,x−1,x,x+1,x+2,x+3
Their sum is
7x=43(x+3)
Solving we get:
x=1217
The largest number is x+3=1217+31=6317
Which is not an integer and the question is flawed.