41−3√3+3√9.
We can write (1 - 3) as ( 1 - 3^(1/3)) ( 1 + 3^(1/3) + 3^(2/3) )
Mulitiplying the numerator and denominator of the first fraction by the last factor in red we get
4 [ 1 + 3^(1/3) + 3^(2/3) ] -2 [ 1 + 3^(1/3) + 3^(2/3) ]
____________________ =
1 - 3
And 9^(1/3) = ( 3^2)^(1/3) = 3^(2/3)
So we have
-2 [ 1 + 3^(1/3) + 3^(2/3) ] + 3^(2/3) =
-2 - 2*3^(1/3) - 3^(2/3)