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xy+5y+4x+20=1

 Nov 7, 2019
 #1
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Are you looking for the possible values of x and y?

 

In that case, let's factor it!

 

xy + 5y + 4x + 20 = 1

y ( x + 5 ) + 4 ( x + 5 ) = 1

( y + 4 ) ( x + 5 ) = 1 

 

Since 1 can ony be represented as 1 * 1 or (-1) * (-1), the only "friendly" integer solutions I see are...

 

x = -6, y = -5                  (-6, -5)

x = -4, y = -3                  (-4, -3)

 Nov 7, 2019

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