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# Algebra

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The equation y = -16t^2 + 28t + 180 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 180 feet from the ground. In how many seconds will the ball hit the ground?

May 6, 2022

#1
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We can set y to 0, and solve for this quadratic.

This will yield: $$0=-16t^2+28t+180$$

We now have a quadratic, and can use this formula: $$t = {-b \pm \sqrt{b^2-4ac} \over 2a}$$ to solve for t, because the equation is in the form $$ax^2+bx+c=0$$.

Can you take it from here?

May 6, 2022