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The equation y = -16t^2 + 28t + 180 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 180 feet from the ground. In how many seconds will the ball hit the ground?

 May 6, 2022
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We can set y to 0, and solve for this quadratic. 

 

This will yield: \(0=-16t^2+28t+180\)

 

We now have a quadratic, and can use this formula: \(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\) to solve for t, because the equation is in the form \(ax^2+bx+c=0\).

 

Can you take it from here?

 May 6, 2022

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