+0  
 
0
100
1
avatar

r and s are the roots of 3x^2 + 4x + 12 = 2x^2 - 8x + 7. Find r^2+s^2

 May 31, 2022
 #1
avatar+2448 
0

We can simplify the expression to: \(x^{2}+12x+5=0\).

 

By Vieta's formula, the sum of the roots (\(r + s\)), equals \({-12 \over 1} = -12 \), and the product of the roots (\(r \times s \)) equals \({5 \over 1 } = 5 \).

 

Note that \(r^2 + s^2 = (r+s)^2 - 2rs\)

 

Can you take it from here?

 May 31, 2022

28 Online Users

avatar
avatar
avatar