+2666 We can simplify the expression to: \(x^{2}+12x+5=0\).
By Vieta's formula, the sum of the roots (\(r + s\)), equals \({-12 \over 1} = -12 \), and the product of the roots (\(r \times s \)) equals \({5 \over 1 } = 5 \).
Note that \(r^2 + s^2 = (r+s)^2 - 2rs\).
Can you take it from here?
