Two of the roots of ax^4 + bx + c = 0 are -3 and 8. Find b.
Let a = 1
So
( x + 3) ( x - 8) = 0
x^2 -5x - 24 = 0
b = -5
[P.S. - the value of "a" = 1 is arbitrary.......other values of b are possible with other choices of "a" ]
