+0  
 
0
79
1
avatar

Two of the roots of ax^4 + bx + c = 0 are -3 and 8. Find b.

 Jul 28, 2022
 #1
avatar+124676 
+1

Let a  =  1

 

So

 

( x + 3) ( x - 8)    =  0

 

x^2 -5x - 24  =  0

 

b  = -5

 

[P.S. -   the value of "a" = 1  is  arbitrary.......other values of  b are possible  with other choices of "a"  ]

 

cool cool cool

 Jul 28, 2022
edited by CPhill  Jul 28, 2022

31 Online Users

avatar