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Two of the roots of ax^4 + bx + c = 0 are -3 and 8. Find b.

 Jul 28, 2022
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Let a  =  1

 

So

 

( x + 3) ( x - 8)    =  0

 

x^2 -5x - 24  =  0

 

b  = -5

 

[P.S. -   the value of "a" = 1  is  arbitrary.......other values of  b are possible  with other choices of "a"  ]

 

cool cool cool

 Jul 28, 2022
edited by CPhill  Jul 28, 2022

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