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order from least to greatest:

$\sqrt{21}$, $\sqrt[3]{27}$, $-\sqrt{64}$, $\sqrt[4]{25}$, $\sqrt{40}$, $-\sqrt[3]{81}$

 Apr 16, 2022
 #1
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\($\sqrt{21}$, $\sqrt[3]{27}$, $-\sqrt{64}$, $\sqrt[4]{25}$, $\sqrt{40}$, $-\sqrt[3]{81}$ \)

 

 

sqrt (21)  =  (4. and some  decimal)

 

cube root  27  = 3

 

-sqrt (64)     = -8

 

4th root of 25  =  (5^2)^(1/4)  = 5^(1/2)  = sqrt 5  =  ( 2. and  some  decimal)  

 

sqrt 40  = 6.and some  decimal

 

-cube root of 81  =    ( -4. and some decimal )

 

You should be able to  do this, now

 

 

cool cool cool

 Apr 16, 2022

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