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Find the positive difference between the solutions to the equation 6t^2 + 30 = 47t.

 Sep 16, 2021
 #1
avatar+35058 
+2

6t^2 -47t+30 = 0

   Use quadratic Formula    to find the roots        a = 6        b = -47         c = 30

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)         

 Sep 17, 2021
 #2
avatar+2246 
+1

Yep, you could also first subtract the quadratic solutions, from the quadratic equation. :))

(-b+sqrt(b^2 - 4ac))/2a - (-b-sqrt(b^2 - 4ac))/2a

sqrt(b^2 - 4ac)/a

Remember that we're looking for the positive difference.

 

=^._.^=

catmg  Sep 17, 2021

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