Find the positive difference between the solutions to the equation 6t^2 + 30 = 47t.
6t^2 -47t+30 = 0
Use quadratic Formula to find the roots a = 6 b = -47 c = 30
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
Yep, you could also first subtract the quadratic solutions, from the quadratic equation. :))
(-b+sqrt(b^2 - 4ac))/2a - (-b-sqrt(b^2 - 4ac))/2a
sqrt(b^2 - 4ac)/a
Remember that we're looking for the positive difference.
=^._.^=
+37146 
