Evaluate the infinite geometric series: 1 + 2/7 + 4/49 + 8/343 + ...
Well, I see (2/7)0 + (2/7)1 + (2/7)2 + (2/7)3 + . . .
but I don't know what to do after that.
Hello Guest,
Solution:
1+27+449+8343+ ...
Like Guest said it right (2/7)0+(2/7)1+(2/7)2+(2/7)3+ ...
Use the double summation sign ∑ .
∞∑n=1(72)1−n=75=1.4 .
Straight