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Positive real numbers x,y satisfy the equations x^2 + y^2 = 1 and x^4 + y^4= 5/8 . Find xy.

 Oct 4, 2021
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\((x^2 + y^2)^2 = x^4 + 2(xy)^2 + y^2\\\\ 1 = \frac{5}{8}+2(xy)^2\)

 

Can you take it from here?

 Oct 5, 2021

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