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Suppose a\neq 0. Compute \log_{8a} b in terms of a and b.

 Apr 30, 2024
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We want to put \(\log_{8a} b\) in terms of a and b. 

 

It's actually not that hard. 

 

We just have

\(\frac{ log(b)}{ log (8a)} = \frac{log( b)}{ log (8) + log (a) }\)

 

That's the best I could do.

 

Thanks! :)

 Jun 8, 2024

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