Suppose a\neq 0. Compute \log_{8a} b in terms of a and b.
We want to put \(\log_{8a} b\) in terms of a and b.
It's actually not that hard.
We just have
\(\frac{ log(b)}{ log (8a)} = \frac{log( b)}{ log (8) + log (a) }\)
That's the best I could do.
Thanks! :)
+1894 
