Suppose a\neq 0. Compute \log_{8a} b in terms of a and b.

We want to put \(\log_{8a} b\) in terms of a and b.

It's actually not that hard.

We just have

\(\frac{ log(b)}{ log (8a)} = \frac{log( b)}{ log (8) + log (a) }\)

That's the best I could do.

Thanks! :)