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Let
f(x) = \left\lfloor\frac{2 - 3x}{3x + 1}\right\rfloor.
Evaluate f(1)+f(2) + f(3) + \dots + f(999)+f(1000). (This sum has 1000 terms, one for the result when we input each integer from 1 to 1000 into f.)

 Jul 18, 2024
 #1
avatar+280 
+1

The answer is \(0\)

 Jul 18, 2024

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