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f(x)=(16*64)^0+64^2/3
 Feb 1, 2012
 #1
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*f(x)=(16*64)^0+64^2/3
-Distribute the 0
*f(x)= (16*0)+(64*0)+64^2/3

-making f(x)=64^2/3
*f(x)=0+64^2/3

-when you are going to enter powers that are fractions in the calculators make sure to use Parenthesis "()"
*f(x)=64^(2/3)

-multiply 64 and it's power = 64^(2/3) = 16, so f(x) aka y=16
 Feb 1, 2012
 #2
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Answer Is = ( 16*64)^0 + 64^ 2/3

f(x) = 1+ \sqrt[2/3]{4^3}

= 1 + (4^{3})^\frac{2}{3}

f(x) = 1 + 16


Having issue with Algebra Help - http://math.tutorvista.com/algebra.html continue studying my future answers.
 Jul 10, 2013

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