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Find the largest value of $x$ such that $3x^2 + 17x + 15 = 2x^2 + 21x + 12 - 5x^2 + 17x + 34.$

 Jul 23, 2024
 #2
avatar+1786 
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First, let's combine all like terms and moving all terms to one side. 

We get the equation

\(6x^{2}-21x-31=0\)

 

Using the quadratic equation, we find two values of x. we have

\(x=\frac{\sqrt{1185}+21}{12}\\ x=\frac{-\sqrt{1185}+21}{12}\)

 

Obviously, the first term of x is bigger, so taking that, we find our final answer as

\(x=\frac{\sqrt{1185}+21}{12}\)

 

Thanks! :)

 Jul 23, 2024
edited by NotThatSmart  Jul 23, 2024

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