If x^5 + 2x^3 + ax^2 + b is divisible by x^3 + 1, then find a and b.
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\(\large \frac{x^5+2x^3+ax^2+b}{x^3+1}\)
\((x^5+2x^3+ax^2+b):(x^3+1)=x^2+2\)
\(\underline{x^5}\) \(\underline{+\ x^2}\)
\(2x^3\) - - \(+\ b\)
\(\underline{2x^3}\) \(\underline{+\ 2} \)
- - - -
\(ax^2-x^2=0\) \(b-2=0\)
a = 1 b = 2
!
asinus
