+0  
 
0
578
1
avatar

1.6491633333=(1.023)^2n how do you bring down the "n" to solve for the variable?

 Aug 23, 2016
 #1
avatar+33653 
0

Take logs of both sides:

 

ln(1.6491633333)=ln((1.023)^2n)  where ln represents log to the base e

 

Now use the property  ln(x^a) = a*ln(x) to get;

 

 ln(1.6491633333)=2n*ln(1.023)

 

Rearrange:  n = ln(1.6491633333)/(2*ln(1.023))

 

You can use a calculator to evaluate this.

 Aug 23, 2016

0 Online Users