We are looking to factor 23x^2 + kx - 5. Some values of k allow us to factor it as a product of linear binomials with integer coefficients. What are all such values of k?

Guest Jun 7, 2023

#1**0 **

We can factor the given polynomial as follows:

23x^2 + kx - 5 = (23x - 5)(x + 1)

The only way this can be factored into a product of linear binomials with integer coefficients is if k is a multiple of 5. This is because the coefficient of the x term must be divisible by 23, and the coefficient of the constant term must be divisible by 5. The only multiples of 5 that are also multiples of 23 are 5, 10, 15, and 20. Therefore, the possible values of k are 5, 10, 15, and 20.

Here is a table showing the factorization of 23x^2 + kx - 5 for each possible value of k:

k | Factorization

5 | (23x - 5)(x + 1)

10 | (23x - 10)(x + 1)

15 | (23x - 15)(x + 1)

20 | (23x - 20)(x + 1)

Guest Jun 7, 2023