Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
36
1
avatar+950 

Let u and v be the solutions to 3x^2 + 5x + 7 = 2x^2 + 11x - 6. Find u/v^2 + v/u^2.

 Jun 22, 2024
 #1
avatar+1950 
+1

First, let's simplify the equation. We have

x26x+13

 

Since the constant is equal to uv, we have the equation

uv=132uv=26

 

The coefficient of x is equal to u+v, so we have

u+v=6

 

Squaring both sides of the equation, we have the equation

u2+2uv+v2=36u2+26+v2=36u2+v2=10

 

Now, it's time for the fun part of this problem. We can simplify what we want to figure out to

u/v2+v/u2=[u3+v3]/[uv]2

We already know all these terms! We can easily find them! We have

u3+v3=(u+v)(u2+v2uv)=(6)(1013)=18[uv]2=[13]2=169

 

Thus, our answer is u/v2+v/u2=[u3+v3]/[uv]2=18/169

 

So -18/169 is our answer. 

 

Thanks! :)

 Jun 22, 2024

2 Online Users

avatar
avatar