step 1: expand
\(2x(x-1)=2x^2-2x\)
\(2x^2-2x=-50\)
We hen add 50 to both sides to get the quadratic
\(2x^2-2x+50=0\)
Applying Vietas, we have the sum of the roots is \(-b/a\) and the product is \(c/a\) where \(ax^2+bx+c=0\)
so we have \(2/2=\boxed{1}\)
