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What is the sum of all possible values of x such that 2x(x - 1) = -50?

 Mar 10, 2021
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step 1: expand

 

\(2x(x-1)=2x^2-2x\)

 

\(2x^2-2x=-50\)

 

We hen add 50 to both sides to get the quadratic

 

\(2x^2-2x+50=0\)

 

Applying Vietas, we have the sum of the roots is \(-b/a\) and the product is \(c/a\) where \(ax^2+bx+c=0\)

 

so we have \(2/2=\boxed{1}\)

 Mar 10, 2021

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