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# algebra

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Two positive numbers and have the property that their sum is equal to their product. If their difference is 7, what is $$\frac{1}{\frac{1}{p^2}+\frac{1}{q^2}}$$? Your answer will be of the form $$\frac{a+b\sqrt{c}}{d}$$, where a and b don't both share a common factor with d and c has no square as a factor. Find a+b+c+d.

Jan 8, 2019

#3
+27342
+3

Here's my go at this (I might also have made a careless error!):

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Jan 8, 2019

#2
+95179
+1

I got

2809+155+53+2332 = 5349

It would have been easy for me to make a careless error

Jan 8, 2019
edited by Melody  Jan 8, 2019
#3
+27342
+3

Here's my go at this (I might also have made a careless error!):

.

Alan Jan 8, 2019
#4
+94526
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Very nice, Alan.....!!!!

CPhill  Jan 8, 2019