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Two positive numbers and have the property that their sum is equal to their product. If their difference is 7, what is \(\frac{1}{\frac{1}{p^2}+\frac{1}{q^2}}\)? Your answer will be of the form \(\frac{a+b\sqrt{c}}{d}\), where a and b don't both share a common factor with d and c has no square as a factor. Find a+b+c+d.

 Jan 8, 2019

Best Answer 

 #3
avatar+27547 
+3

Here's my go at this (I might also have made a careless error!):

 

.

 Jan 8, 2019
 #2
avatar+99331 
+1

I got 

 

2809+155+53+2332 = 5349

 

It would have been easy for me to make a careless error

 

If you care about how the answer was derived you can always ask.   laugh

 Jan 8, 2019
edited by Melody  Jan 8, 2019
 #3
avatar+27547 
+3
Best Answer

Here's my go at this (I might also have made a careless error!):

 

.

Alan Jan 8, 2019
 #4
avatar+98172 
0

Very nice, Alan.....!!!!

 

 

cool cool cool

CPhill  Jan 8, 2019

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