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avatar+388 

Let f(x) = lfloor (2 - 3x)/(3x + 8) \rfloor
Evaluate $f(1)+f(2) + f(3) + \dots + f(999)+f(1000).$ (This sum has $1000$ terms, one for the result when we input each integer from $1$ to $1000$ into $f$.)

 May 24, 2024
 #1
avatar+129499 
+1

floor [ (2 -3x) / (3x + 8) ]

 

The value  of  f(1)  to f(1000)  always =   -1

 

So....the sum is  -1000 

 

cool cool cool

 May 24, 2024

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