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Find the discriminant of the quadratic 5x^2 - 2x + 8 - 2x^2 + 6x + 2 - 2x^2 + 4x - 1.

 Jun 8, 2024

Best Answer 

 #1
avatar+1365 
+1

First, let's combine all like terms to get a real quadratic. 

 

We get \(x^{2}+8x+9\).

 

The descriminant of the quadratic is \(b^2-4ac\) for those in \(ax^2+bx+c\)

 

We have \(8^2-4(1)(9) = 64-36=28\)

 

So 28 is our answer!

 

Thanks! :)

 Jun 8, 2024
 #1
avatar+1365 
+1
Best Answer

First, let's combine all like terms to get a real quadratic. 

 

We get \(x^{2}+8x+9\).

 

The descriminant of the quadratic is \(b^2-4ac\) for those in \(ax^2+bx+c\)

 

We have \(8^2-4(1)(9) = 64-36=28\)

 

So 28 is our answer!

 

Thanks! :)

NotThatSmart Jun 8, 2024

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