+0  
 
0
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For a real number x, find the number of different possible values of x^2 - abs(x)^2.

 Feb 15, 2022
 #1
avatar
0

one.

 Feb 15, 2022
 #2
avatar+124594 
+2

x^2 - l x^2 l

 

Note that the absolute value of  x^2  =  x^2

 

So......this always evaluates to   0

 

 

cool cool cool

 Feb 15, 2022
 #3
avatar+726 
+7

Yes you are very right.

 

For anyone reading this solution, x has to be a real number as declared in the question, thus x^2 - |x^2| could not be negative... 

x can't be i.

smiley

proyaop  Feb 16, 2022

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