The parabola $y = ax^2 + bx + c$ is graphed below. Find $a \cdot b \cdot c.$ (The grid lines are one unit apart.)
x coordinate of vertex = 3 = -b/ (2a)
So....
6a = -b
b = -6a
Since (0,7) is on the graph, then
c = 7
We have
1 = a(3)^2 - 6a(3) + 7
-6 = 9a - 18a
-6 = -9a
a = 2/3
b = -6a = -6(2/3) = -4
a*b*c = (2/3) (-4) (7) = -56 / 3