Algebra

$1 + \dfrac{3}{6} + \dfrac{15}{6^2} + \dfrac{27}{6^3}\\ =\dfrac{6^3+3\cdot 6^2+15\cdot 6+27}{6^3}\\ =\dfrac{441}{6^3}\\ =\dfrac{3^2\cdot 7^2}{2^3\cdot 3^3}\\ \color{blue}=\dfrac{7^2}{2^3\cdot3}$

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