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Find the largest integer k such that the equation 5x^2 - kx + 8 - 2x^2 + 25 =0 has no real solutions

 Aug 4, 2024
 #1
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First, let's simplify and combine all like terms. 

After doing that, we get \(3x^2-kx+33=0\)

 

Now, in order for the equation to have no real solutions, the descriminant must be less than 0. 

The descriminant is \(b^2-4ac\), so we have the equation \(k^2 - 4(33)(3) < 0\)

 

Since we are trying to find the largest, we set the two to equal each other and get

\(k^2 - 396 = 0\\ k^2 = 396\\ k \approx 19.89974\)

 

Rounding down, the largest k can be as an integer is 19. 

So our answer is 19. 

 

Thanks! :)

 Aug 4, 2024
edited by NotThatSmart  Aug 4, 2024

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