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Let f(x) = \sqrt{x}
Find the largest three-digit value of x such that f(x) is an integer.

 Jul 8, 2024
 #1
avatar+1275 
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Let's note something for this problem first. 

We are basically taking a look at the squares of numbers, and eeing the largest 3 digit number. 

 

Thus, let's test some integers. We find that

\(31^2 = 961 \\ 32^2 = 1024 \)

 

This shows that 31 is the largest value squared. 

Thus, 961 is our answer. 

 

So we have \(x=961\)

 

Thanks! :)

 Jul 8, 2024

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