Let f(x) = \sqrt{x}

Find the largest three-digit value of x such that f(x) is an integer.

kittykat Jul 8, 2024

#1**+1 **

Let's note something for this problem first.

We are basically taking a look at the squares of numbers, and eeing the largest 3 digit number.

Thus, let's test some integers. We find that

\(31^2 = 961 \\ 32^2 = 1024 \)

This shows that 31 is the largest value squared.

Thus, 961 is our answer.

So we have \(x=961\)

Thanks! :)

NotThatSmart Jul 8, 2024