Let f(x) = \sqrt{x}
Find the largest three-digit value of x such that f(x) is an integer.
Let's note something for this problem first.
We are basically taking a look at the squares of numbers, and eeing the largest 3 digit number.
Thus, let's test some integers. We find that
312=961322=1024
This shows that 31 is the largest value squared.
Thus, 961 is our answer.
So we have x=961
Thanks! :)