How many integers satisfy the inequality x(3x-4)<=6x^2-3x+5 divided by 10 ?
\(x(3x-4)<=6x^2-3x+5/10?\)
+154 if its the whole right side divided by 10 then:
so to sum it up:
1) solve the inequality as if it's a regular equation
2) find the two "boundary" points (what x equals to)
3) [optional] draw a number line and put those points on the line
4) test the values created by the 3 sections (one smaller than the value of the lower boundary, one in between both, one larger than the value of the upper boundary)
5) if the test passes, then the section containing that value is a part of the solution set
6) count the integers
